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evaluate the given limit x 1 ax 2 bx c cx 2 bx a a
Question:
Evaluate the Given limit:
\(\lim_{x\rightarrow 1}\)
\(\frac{ax^2+bx+c}{cx^2+bx+a}\)
, a + b + c ≠0
CBSE Class XI
Updated On:
Oct 23, 2023
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Solution and Explanation
∴
\(\lim_{x\rightarrow 1}\)
\(\frac{ax^2+bx+c}{cx^2+bx+a}\)
=
\(\frac{a(1)^2+b(1)^2+c}{c(1)^2+b(1)+a}\)
=
\(\frac{a+b+c}{a+b+c}\)
=1 [a+b+c
\(\neq\)
0]
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