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evaluate cosh 1 2
Question:
Evaluate:
\[ \cosh^{-1} 2 \]
Show Hint
For \( \cosh^{-1} x \), use \( \cosh^{-1} x = \log (x + \sqrt{x^2 - 1}) \).
AP EAMCET - 2024
AP EAMCET
Updated On:
May 21, 2025
\( \log(2 + \sqrt{3}) \)
\( \log(2 + \sqrt{5}) \)
\( \log(2 - \sqrt{5}) \)
\( \log(2 + \sqrt{2}) \)
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The Correct Option is
A
Solution and Explanation
The formula for inverse hyperbolic cosine is: \[ \cosh^{-1} x = \log \left( x + \sqrt{x^2 - 1} \right) \] Substituting \( x = 2 \): \[ \cosh^{-1} 2 = \log \left( 2 + \sqrt{2^2 - 1} \right) \] \[ = \log (2 + \sqrt{4 - 1}) = \log (2 + \sqrt{3}) \] Thus, the correct answer is \( \log(2 + \sqrt{3}) \).
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