Equivalent statement to (p\(\to\)q) \(\vee\) (r\(\to\)q) will be
(p \(\wedge\) r) \(\to\) q
(p \(\vee\) r) \(\to\) q
(q \(\to\) r) \(\vee\) (p \(\vee\) r)
(r \(\to\) p) \(\wedge\) (q \(\to\) r)
| p | q | r | p → q | r → q | (p → q) \(\vee\) (r → q) | (p \(\wedge\) r) | (p \(\wedge\) r) → q |
| T | T | T | T | T | T | T | T |
| T | T | F | T | T | T | F | T |
| T | F | T | F | F | F | T | F |
| T | F | F | F | T | T | F | T |
| F | T | T | T | T | T | F | T |
| F | T | F | T | T | T | F | T |
| F | F | T | T | F | T | F | T |
| F | F | F | T | T | T | F | T |
In the given figure, the blocks $A$, $B$ and $C$ weigh $4\,\text{kg}$, $6\,\text{kg}$ and $8\,\text{kg}$ respectively. The coefficient of sliding friction between any two surfaces is $0.5$. The force $\vec{F}$ required to slide the block $C$ with constant speed is ___ N.
(Given: $g = 10\,\text{m s}^{-2}$) 
Mathematical reasoning or the principle of mathematical reasoning is a part of mathematics where we decide the truth values of the given statements. These reasoning statements are common in most competitive exams like JEE and the questions are extremely easy and fun to solve.
Mathematically, reasoning can be of two major types such as: