Equal weights of methane and hydrogen are mixed in an empty container at $25^\circ$ C The fraction of the total pressure exerted by hydrogen is
- $\frac{1}{2}$
- $\frac{8}{9}$
- $\frac{18}{17}$
- $\frac{16}{17}$
The Correct Option is B
Solution and Explanation
The correct option is(B): \(\frac{8}{9}\).
Let .v grams of each hydrogen and methane are mixed
\(\, \, \, \, \, \, \, \, \, \, \, \, \, \, \, Moles\, of\, H_2=\frac{x}{2}\)
\(\, \, \, \, \, \, \, \, \, \, \, \, \, \, \, Moles\, of\, CH_4=\frac{x}{16}\)
\(\Rightarrow \, \, \, \, \, \, Mole fraction of H_2 =\frac{\frac{x}{2}}{\frac{x}{2}+\frac{x}{16}}=\frac{8}{9}\)
\(\Rightarrow \, \, \, \, \frac{Partial\, pressure\, of\, H_2}{Total\, pressure }=Mole\, fraction\, of\, H_2=\frac{8}{9}\)
Top Questions on States of matter
- Statement-1: Sublimation is a purification technique that is used to separate those solid substances which change from solid to vapor state without passing through liquid state.
Statement-2: If external atmospheric pressure is reduced, then boiling point of substance decreases.
Which of the following is correct?
- JEE Main - 2026
- Chemistry
- States of matter
- Given below are two statements: Statement I: Sublimation is a purification technique that is used to separate those solid substances which change from solid to vapour state without passing through liquid state. Statement II: If external atmospheric pressure is reduced, then boiling point of a substance is decreased. In the light of the above statements, choose the correct option.
- JEE Main - 2026
- Chemistry
- States of matter
- $10^{-6} \text{ M } \text{NaOH}$ is diluted 100 times. The $\text{pH}$ of the diluted base is:
- LPUNEST - 2026
- Chemistry
- States of matter
- $1.0 \times 10^{-4} \text{ M } \text{HCl}$ is diluted 10 times. The $\text{pH}$ of the final solution is:
- LPUNEST - 2026
- Chemistry
- States of matter
- What is the relation between \( \Delta G \) and \( E_{\text{cell}} \)?
- GUJCET - 2025
- Chemistry
- States of matter
Questions Asked in JEE Advanced exam
- Let $ x_0 $ be the real number such that $ e^{x_0} + x_0 = 0 $. For a given real number $ \alpha $, define $$ g(x) = \frac{3xe^x + 3x - \alpha e^x - \alpha x}{3(e^x + 1)} $$ for all real numbers $ x $. Then which one of the following statements is TRUE?
- JEE Advanced - 2025
- Fundamental Theorem of Calculus
- A linear octasaccharide (molar mass = 1024 g mol$^{-1}$) on complete hydrolysis produces three monosaccharides: ribose, 2-deoxyribose and glucose. The amount of 2-deoxyribose formed is 58.26 % (w/w) of the total amount of the monosaccharides produced in the hydrolyzed products. The number of ribose unit(s) present in one molecule of octasaccharide is _____.
Use: Molar mass (in g mol$^{-1}$): ribose = 150, 2-deoxyribose = 134, glucose = 180; Atomic mass (in amu): H = 1, O = 16- JEE Advanced - 2025
- Biomolecules
Let $ P(x_1, y_1) $ and $ Q(x_2, y_2) $ be two distinct points on the ellipse $$ \frac{x^2}{9} + \frac{y^2}{4} = 1 $$ such that $ y_1 > 0 $, and $ y_2 > 0 $. Let $ C $ denote the circle $ x^2 + y^2 = 9 $, and $ M $ be the point $ (3, 0) $. Suppose the line $ x = x_1 $ intersects $ C $ at $ R $, and the line $ x = x_2 $ intersects $ C $ at $ S $, such that the $ y $-coordinates of $ R $ and $ S $ are positive. Let $ \angle ROM = \frac{\pi}{6} $ and $ \angle SOM = \frac{\pi}{3} $, where $ O $ denotes the origin $ (0, 0) $. Let $ |XY| $ denote the length of the line segment $ XY $. Then which of the following statements is (are) TRUE?
- JEE Advanced - 2025
- Conic sections
- Adsorption of phenol from its aqueous solution on to fly ash obeys Freundlich isotherm. At a given temperature, from 10 mg g$^{-1}$ and 16 mg g$^{-1}$ aqueous phenol solutions, the concentrations of adsorbed phenol are measured to be 4 mg g$^{-1}$ and 10 mg g$^{-1}$, respectively. At this temperature, the concentration (in mg g$^{-1}$) of adsorbed phenol from 20 mg g$^{-1}$ aqueous solution of phenol will be ____. Use: $\log_{10} 2 = 0.3$
- JEE Advanced - 2025
- Adsorption
- At 300 K, an ideal dilute solution of a macromolecule exerts osmotic pressure that is expressed in terms of the height (h) of the solution (density = 1.00 g cm$^{-3}$) where h is equal to 2.00 cm. If the concentration of the dilute solution of the macromolecule is 2.00 g dm$^{-3}$, the molar mass of the macromolecule is calculated to be $X \times 10^{4}$ g mol$^{-1}$. The value of $X$ is ____. Use: Universal gas constant (R) = 8.3 J K$^{-1}$ mol$^{-1}$ and acceleration due to gravity (g) = 10 m s$^{-2}\}$
- JEE Advanced - 2025
- Colligative Properties
Concepts Used:
States of Matter
The matter is made up of very tiny particles and these particles are so small that we cannot see them with naked eyes.
There are three States of Matter:
The three states of matter are as follows:
Solid State:
- The solid-state is one of the fundamental states of matter.
- Solids differ from liquids and gases by the characteristic of rigidity.
- The molecules of solids are tightly packed because of strong intermolecular forces; they only oscillate about their mean positions.
Liquid State:
- The molecules in a liquid are closely packed due to weak intermolecular forces.
- These forces are weaker than solids but stronger than that of gases.
- There is much space in between the molecules of liquids which makes their flowing ability easy.
Gaseous State:
- In this state of matter, distances between the molecules are large (intermolecular distance is in the range of 10-7-10-5 cm.
- The intermolecular forces experienced between them are negligible.
- Thus, translatory, rotatory and vibratory motions are observed prominently in gases.