Question:

Entropy decreases in which of the following reactions? $ \text{(A) } \text{Br}_2 (l) \to \text{Br}_2 (g) $ $ \text{(B) } \text{Br}_2 (g) \to \text{Br}_2 (l) $ $ \text{(C) } \text{Br}_2 (l) \to \text{Br}_2 (g) \text{ and } \text{Br}_2 (g) \to \text{Br}_2 (l) $

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For phase transitions, the general rule is: gas to liquid or solid results in a decrease in entropy, while liquid to gas or solid to liquid results in an increase in entropy.
Updated On: Apr 28, 2025
  • \( \text{Br}_2 (l) \to \text{Br}_2 (g) \)
  • \( \text{Br}_2 (g) \to \text{Br}_2 (l) \)
  • Both A and B
  • None of the above
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The Correct Option is B

Solution and Explanation

Entropy is a measure of the disorder or randomness of a system. For a phase transition, such as from liquid to gas, entropy increases due to the increase in the freedom of motion of molecules in the gas phase. In the reaction: \[ \text{Br}_2 (l) \to \text{Br}_2 (g) \] there is a phase transition from liquid to gas, which increases entropy. However, when the phase transition is from gas to liquid: \[ \text{Br}_2 (g) \to \text{Br}_2 (l) \] the molecules in the gas phase become more ordered when they condense into the liquid phase, which results in a decrease in entropy.
Thus, entropy decreases in the reaction \( B \).
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