Question:

Electromagnetic waves are incident normally on a perfectly reflecting surface having surface area A. If I is the intensity of the incident electromagnetic radiation and c is the speed of light in vacuum, the force exerted by the electromagnetic wave on the reflecting surface is

Updated On: Mar 29, 2025
  • \(\frac{2IA}{c}\)
  • \(\frac{IA}{c}\)
  • \(\frac{IA}{2c}\)
  • \(\frac{I}{2Ac}\)
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The Correct Option is A

Solution and Explanation

Given:

  • Surface area = \( A \)
  • Intensity of electromagnetic wave = \( I \)
  • Speed of light in vacuum = \( c \)
  • Surface is perfectly reflecting

Step 1: Radiation Pressure

For a **perfectly reflecting** surface, the radiation pressure \( P \) is given by:

\[ P = \frac{2I}{c} \]

Step 2: Force on the Surface

Force exerted by radiation is pressure multiplied by area:

\[ F = P \cdot A = \frac{2I}{c} \cdot A = \frac{2IA}{c} \]

The force exerted by the wave is \({\frac{2IA}{c}} \), so the correct answer is (A).

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