Electric charge is transferred to an irregular metallic disk as shown in the figure. If $ \sigma_1 $, $ \sigma_2 $, $ \sigma_3 $, and $ \sigma_4 $ are charge densities at given points, then choose the correct answer from the options given below:
In this problem, we are dealing with charge distribution on an irregular metallic disk.
The charge density on the surface of a conductor is not uniform and depends on the geometry of the conductor and the position on the conductor.
For a metallic disk:
- The charge densities at the edge are generally higher due to the fact that charges tend to accumulate at points of sharp curvature, such as the corners of the disk.
- The charge densities at the flat portions of the disk, away from the edges, are generally lower.
Looking at the figure:
- \( \sigma_1 \), being near the top edge of the disk, would have a higher charge density than \( \sigma_3 \), which is closer to the center.
- \( \sigma_2 \), being near the edge, would also have a higher charge density than \( \sigma_4 \), which is farther away from the edge.
Thus: - \( \sigma_1>\sigma_3 \)
- \( \sigma_2 = \sigma_4 \) (due to symmetry of the disk)
Therefore, the correct options are A, B, and C, meaning \( \sigma_1>\sigma_3 \), and \( \sigma_2 = \sigma_4 \).
For the thermal decomposition of \( N_2O_5(g) \) at constant volume, the following table can be formed, for the reaction mentioned below: \[ 2 N_2O_5(g) \rightarrow 2 N_2O_4(g) + O_2(g) \] Given: Rate constant for the reaction is \( 4.606 \times 10^{-2} \text{ s}^{-1} \).
Let \( T_r \) be the \( r^{\text{th}} \) term of an A.P. If for some \( m \), \( T_m = \dfrac{1}{25} \), \( T_{25} = \dfrac{1}{20} \), and \( \displaystyle\sum_{r=1}^{25} T_r = 13 \), then \( 5m \displaystyle\sum_{r=m}^{2m} T_r \) is equal to: