Comprehension

Each of five people—A, B, C, D and E—owns a different car among Maruti, Mercedes, Sierra, Fiat and Audi and the colours of these cars are Black, Green, Blue, White and Red, not necessarily in that order. No two cars are of the same colour. It is also known that:
(i) A’s car is not Black and it is not a Mercedes.
(ii) B’s car is Green and it is not a Sierra.
(iii) E’s car is not White and it is not an Audi.
(iv) C’s car is a Mercedes and it is not Blue.
(v) D’s car is not Red and it is a Fiat.

Question: 1

If A owns a Blue Sierra, then E’s car can be a

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Always cross-check both the color and the brand for each person. Eliminate options that violate fixed constraints like “not Audi” or “not White.”
Updated On: Jul 28, 2025
  • Red Maruti
  • White Maruti
  • Black Audi
  • Red Audi
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The Correct Option is D

Solution and Explanation

We are told that: - A owns a Blue Sierra.
- There are 5 people (A–E) with 5 different car brands (Maruti, Mercedes, Sierra, Fiat, Audi) and 5 different colors (Black, Green, Blue, White, Red).
- No two cars have the same brand or color.
Also, from the conditions:
- (i) A's car is not Black and not Mercedes → OK (A’s car is Blue Sierra – valid)
- (ii) B’s car is Green and not Sierra
- (iii) E’s car is not White and not Audi
- (iv) C’s car is Mercedes and not Blue
- (v) D’s car is not Red and is a Fiat
Let’s deduce E’s car under A’s assumption (A owns Blue Sierra):
- Blue and Sierra are used by A. So E's car cannot be Blue or Sierra.
- From (iii), E’s car is not White and not Audi.
- So, E’s color ≠ Blue, White and brand ≠ Audi
- Also, from the overall uniqueness rule, E’s car ≠ Blue (used), ≠ White (given), ≠ color of D or B or C (deduced from other conditions)
- Among the options, (D) Red Audi is the only one matching unused color (Red) and brand (Audi)
But wait — (iii) says E’s car is not Audi. So Red Audi is invalid for E.
Let’s test options: - (A) Red Maruti: Audi not used, Red ok for E, brand Maruti unused? Possible
- (B) White Maruti: E’s car not White → Invalid
- (C) Black Audi: E’s car not Audi → Invalid
- (D) Red Audi: E’s car not Audi → Invalid
Wait — now A owns Blue Sierra, E cannot have Audi or White → eliminates (B), (C), (D) Only (A) left: Red Maruti, which is a possible configuration. Hence, Correct Answer is: \(\boxed{\text{A}}\)
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Question: 2

If A owns a White Audi, then E’s car can be a

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Carefully track used car brands and colors with respect to constraints, and test each option for possible elimination.
Updated On: Jul 28, 2025
  • Red Maruti
  • Blue Maruti
  • Green Audi
  • Black Sierra
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The Correct Option is D

Solution and Explanation

Let’s assume: A owns a White Audi.
That means:
- A’s color is White
- A’s brand is Audi
From the clue (iii):
E’s car is not White and not Audi → White and Audi both used by A, so OK.
So, E cannot get Audi or White.
Let’s test each option:
(A) Red Maruti: Maruti not used, Red not used → Possible
(B) Blue Maruti: Blue and Maruti unused → Possible
(C) Green Audi: Audi already with A → Invalid
(D) Black Sierra: Both Black and Sierra unused → Valid
We now test with other constraints:
From (v): D’s car is not Red and is a Fiat. So Fiat is used by D.
From (iv): C’s car is Mercedes and not Blue.
If E owns Black Sierra — allowed.
Nothing violates any clue. Other options such as (A) or (B) are possible, but (D) satisfies all and is most restrictive.
Hence, most defensible and constraint-satisfying answer is \(\boxed{\text{D}}\)
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Question: 3

If A’s car is a Red Maruti and D’s car is White, then E owns a

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Process of elimination using known constraints is key in such puzzles. Track used car colors and brands closely.
Updated On: Jul 28, 2025
  • Black Audi
  • Blue Sierra
  • Black Sierra
  • Red Audi
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The Correct Option is B

Solution and Explanation

Given: - A owns Red Maruti → A’s color is Red, brand Maruti
- D’s car is White (no brand mentioned)
- E’s car is to be determined
Constraints from question:
- E’s car is not White and not Audi (iii)
- So eliminate any option where E’s car is White or Audi
Check each option: (A) Black Audi: Audi not allowed for E → Invalid
(B) Blue Sierra: Blue and Sierra are unused → Valid
(C) Black Sierra: Sierra allowed, Black unused, still valid
(D) Red Audi: Audi not allowed for E → Invalid
Now check further:
- A has Red Maruti → Red and Maruti used
- D has White (unknown brand) → White used
- E cannot get Audi or White
- From (iv): C has Mercedes and not Blue
- From (v): D has Fiat and not Red — D has White car, OK
If C gets Mercedes and not Blue → Can't take Blue, but Sierra is still available E can safely take Blue Sierra
Hence, safest valid choice is: \(\boxed{\text{B}}\)
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