Question:

Differential co-efficient of $\log_{10} x $ w.r.t. $log_x 10$ is

Updated On: Jul 6, 2022
  • $ - \frac{(\log x) 2}{(\log 10)^2}$
  • $ \frac{(\log_{10} x) 2}{(\log 10)^2}$
  • $ \frac{(\log_x 10) 2}{(\log 10)^2}$
  • $ - \frac{(\log 10) 2}{(\log x)^2}$
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The Correct Option is A

Solution and Explanation

Let $y = \log_{10} x \,and\,z = \log_{x} 10 = \frac{1}{\log_{10} x} = \frac{1}{y} $ $\therefore y = \frac{1}{z} \therefore \frac{dy}{dz} = - \frac{1}{z^{2}} .$ $ = - \frac{1}{\left(\log_{x} 10\right)^{2}} = - \frac{\left(\log x\right)^{2}}{\left(\log10\right)^{2}} $
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