Step 1: Definition of Kilowatt-hour.
A
kilowatt-hour (kWh) is the amount of energy consumed by a device with a power rating of 1 kilowatt operating for 1 hour. It is a unit of energy commonly used by electric utilities to measure electrical energy consumption.
\[
1 \, \text{kWh} = 1 \, \text{kilowatt} \times 1 \, \text{hour}
\]
Step 2: Conversion of Kilowatt-hour to Joules.
We know that:
\[
1 \, \text{kilowatt} = 1000 \, \text{watts} \quad \text{and} \quad 1 \, \text{hour} = 3600 \, \text{seconds}
\]
Thus, the energy in Joules for 1 kWh is:
\[
1 \, \text{kWh} = 1000 \, \text{watts} \times 3600 \, \text{seconds} = 3,600,000 \, \text{Joules}
\]
So, \( 1 \, \text{kWh} = 3,600,000 \, \text{Joules} \).
Step 3: Calculation of energy consumed by the electric kettle.
The power rating of the electric kettle is 2.2 kilowatts (kW), and it works for 3 hours.
Energy consumed \( E \) is given by the formula:
\[
E = P \times t
\]
where:
- \( P = 2.2 \, \text{kW} \) (power of the kettle),
- \( t = 3 \, \text{hours} \).
Thus:
\[
E = 2.2 \, \text{kW} \times 3 \, \text{hours} = 6.6 \, \text{kWh}
\]
Now, convert energy to Joules:
\[
E = 6.6 \, \text{kWh} \times 3,600,000 \, \text{Joules} = 23,760,000 \, \text{Joules}
\]
Step 4: Calculation of the current.
The electric kettle operates at a voltage of 220 volts, and its power is 2.2 kW.
We can use the formula for electrical power:
\[
P = V \times I
\]
where:
- \( P = 2.2 \, \text{kW} = 2200 \, \text{W} \) (convert to watts),
- \( V = 220 \, \text{V} \) (voltage),
- \( I \) is the current.
Rearranging the formula to solve for current:
\[
I = \frac{P}{V} = \frac{2200}{220} = 10 \, \text{A}
\]
Step 5: Conclusion.
- The energy consumed by the electric kettle in 3 hours is
23,760,000 Joules.
- The current drawn by the electric kettle is
10 amperes.