We are given:
- The rate of change of current, \( \frac{dI}{dt} = 10 \, \text{A/s} \)
- The induced emf, \( \mathcal{E} = 120 \, \text{V} \)
From Faraday’s law of electromagnetic induction, the induced emf is related to the inductance of the coil by:
\[
\mathcal{E} = L \frac{dI}{dt}
\]
Substitute the given values:
\[
120 = L \times 10
\]
Solving for \( L \):
\[
L = \frac{120}{10} = 12 \, \text{H}
\]
Thus, the inductance of the coil is \( 12 \, \text{H} \).