Question

Correlation equations for gas compressibility factor (\( z \)) and viscosity (\( \mu \)) as functions of pressure (\( p \)) are as given below.
\[ z = C_1 p^{-0.25}, \quad \mu = C_2 p^{1.25} \] where \( C_1 \) and \( C_2 \) are constants, consistent with the field units (pressure in psi and viscosity \( \mu \) in cP), and have values 1.96 and \( 7 \times 10^{-4} \), respectively.
Real gas pseudo pressure corresponding to a pressure of 2500 psi is .......... \( \times 10^6 \) psi²/cP (rounded off to two decimal places).

Hint:

When calculating real gas pseudo pressure, make sure to use the correct constants and units. The formula given is crucial for obtaining accurate values for compressibility and viscosity.

Answer 1

The real gas pseudo pressure is calculated using the following formula:
\[ {Pseudo Pressure} = C_1 \times p^{-0.25} \] Substitute the values into the formula:
\[ {Pseudo Pressure} = 1.96 \times 2500^{-0.25} = 3.67 \times 10^6 \, {psi}^2/{cP} \] Thus, the real gas pseudo pressure corresponding to a pressure of 2500 psi is approximately 3.50 to 3.80 x 10⁶ psi²/cP.