Question:

Correct order of stability of carbanion is: 
 

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Aromatic carbanions are the most stable, while anti-aromatic carbanions are the least stable.
Updated On: May 22, 2025
  • \(C>B>D>A\)
  • \(A>B>C>D\)
  • \(D>A>C>B\)
  • \(D>C>B>A\)
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The Correct Option is D

Approach Solution - 1

Step 1: Evaluating Stability Factors
Carbanion stability depends on resonance, hybridization, and inductive effects.
Aromatic stabilization makes carbanions more stable.
Step 2: Stability Order
Compound (D) is aromatic, making it the most stable.
Compound (A) is anti-aromatic and the least stable.
Compounds (B) and (C) are less stable due to lack of delocalization.
Thus, the correct answer is (D).
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Approach Solution -2

Step 1: Identify the carbanion structures
We are given four cyclic carbanions:
a) Cyclopropyl anion (3-membered ring)
b) Cyclobutyl anion (4-membered ring)
c) Cyclopentyl anion (5-membered ring)
d) Cyclopentadienyl anion (5-membered ring with conjugated double bonds)

Step 2: Understand what affects carbanion stability
Carbanion stability is influenced by:
- Electron delocalization (resonance)
- Inductive effects
- Aromaticity
- Angle strain in ring systems

Step 3: Analyze each structure
Option D: Cyclopentadienyl anion
Aromatic compound (6 π electrons, cyclic, planar, follows Huckel’s rule)
Negative charge is delocalized over the ring
Very stable due to aromaticity

Option C: Cyclopentyl anion
No resonance stabilization
Low ring strain in 5-membered ring
Moderate stability

Option B: Cyclobutyl anion
No resonance stabilization
Significant ring strain in 4-membered ring
Less stable than cyclopentyl anion

Option A: Cyclopropyl anion
Highly strained 3-membered ring
No resonance or delocalization
Least stable of all

Step 4: Correct order of stability
D (cyclopentadienyl anion) > C (cyclopentyl anion) > B (cyclobutyl anion) > A (cyclopropyl anion)

Final Answer: \( D > C > B > A \)
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