Question:
Correct order of stability of carbanion is:
Correct order of stability of carbanion is:
Show Hint
Aromatic carbanions are the most stable, while anti-aromatic carbanions are the least stable.
Updated On: Mar 24, 2025
- \(C>B>D>A\)
- \(A>B>C>D\)
- \(D>A>C>B\)
- \(D>C>B>A\)
Hide Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Step 1: Evaluating Stability Factors
Carbanion stability depends on resonance, hybridization, and inductive effects.
Aromatic stabilization makes carbanions more stable.
Step 2: Stability Order
Compound (D) is aromatic, making it the most stable.
Compound (A) is anti-aromatic and the least stable.
Compounds (B) and (C) are less stable due to lack of delocalization.
Thus, the correct answer is (D).
Carbanion stability depends on resonance, hybridization, and inductive effects.
Aromatic stabilization makes carbanions more stable.
Step 2: Stability Order
Compound (D) is aromatic, making it the most stable.
Compound (A) is anti-aromatic and the least stable.
Compounds (B) and (C) are less stable due to lack of delocalization.
Thus, the correct answer is (D).
Was this answer helpful?
0
0
Top Questions on thermal properties of matter
- In YDSE, monochromatic light falls on a screen 1.80 m from two slits separated by 2.08 mm. The first and second order bright fringes are separated by 0.553 mm. The wavelength of light used is:
- BITSAT - 2024
- Physics
- thermal properties of matter
- If the distance between an object and its two times magnified virtual image produced by a curved mirror is 15 cm, the focal length of the mirror must be:
- BITSAT - 2024
- Physics
- thermal properties of matter
- When a light ray incidents on the surface of a medium, the reflected ray is completely polarized. Then the angle between reflected and refracted rays is:
- BITSAT - 2024
- Physics
- thermal properties of matter
- A microwave of wavelength 2.0 cm falls normally on a slit of width 4.0 cm. The angular spread of the central maxima of the diffraction pattern obtained on a screen 1.5 m away from the slit will be:
- BITSAT - 2024
- Physics
- thermal properties of matter
- Power of a biconvex lens is \( P \) diopter. When it is cut into two symmetrical halves by a plane containing the principal axis, the ratio of the power of two halves is:
- BITSAT - 2024
- Physics
- thermal properties of matter
View More Questions
Questions Asked in BITSAT exam
- Let \( ABC \) be a triangle and \( \vec{a}, \vec{b}, \vec{c} \) be the position vectors of \( A, B, C \) respectively. Let \( D \) divide \( BC \) in the ratio \( 3:1 \) internally and \( E \) divide \( AD \) in the ratio \( 4:1 \) internally. Let \( BE \) meet \( AC \) in \( F \). If \( E \) divides \( BF \) in the ratio \( 3:2 \) internally then the position vector of \( F \) is:
- BITSAT - 2024
- Vectors
- Let \( \mathbf{a} = \hat{i} - \hat{k}, \mathbf{b} = x\hat{i} + \hat{j} + (1 - x)\hat{k}, \mathbf{c} = y\hat{i} + x\hat{j} + (1 + x - y)\hat{k} \). Then, \( [\mathbf{a} \, \mathbf{b} \, \mathbf{c}] \) depends on:}
- BITSAT - 2024
- Vectors
- Let the foot of perpendicular from a point \( P(1,2,-1) \) to the straight line \( L : \frac{x}{1} = \frac{y}{0} = \frac{z}{-1} \) be \( N \). Let a line be drawn from \( P \) parallel to the plane \( x + y + 2z = 0 \) which meets \( L \) at point \( Q \). If \( \alpha \) is the acute angle between the lines \( PN \) and \( PQ \), then \( \cos \alpha \) is equal to:
- The magnitude of projection of the line joining \( (3,4,5) \) and \( (4,6,3) \) on the line joining \( (-1,2,4) \) and \( (1,0,5) \) is:
- BITSAT - 2024
- Vectors
- The angle between the lines whose direction cosines are given by the equations \( 3l + m + 5n = 0 \) and \( 6m - 2n + 5l = 0 \) is:
- BITSAT - 2024
- Vectors
View More Questions