Correct order of dissociation energy of \(N_2\) and \(N_2^+\) is:
\(N_2>N_2^+\)
\(N_2=N_2^+\)
\(N_2^+>N_2\)
\(None\)
The order of dissociation energy between \(N_2\) and \(N_2^+\) can be explained based on molecular and electronic structure.
N2 (Nitrogen Molecule):
N2+ (Nitrogen Cation):
In summary, \(N_2\) has a stronger and more stable triple bond, which means that it requires more energy to dissociate into its constituent nitrogen atoms. \(N_2^+\), on the other hand, has a weaker bond due to the loss of an electron, so it requires less energy for dissociation.
Therefore, the correct order of dissociation energy is option (A) \(N_2 > N_2^+\)
Match the LIST-I with LIST-II
LIST-I (Bonds) | LIST-II (Formations) |
---|---|
A. Ionic Bonds | Actual transfer of electrons from one atom to another atom |
B. Metallic Bonds | Partial sharing of valence electrons by the neighboring atoms |
C. Van der Waals Bonds | This type of bonding arises from dipolar interaction of crystals/molecules of the crystal. |
D. Hydrogen Bonds | This type of interaction between the oppositely charged ends of permanently polarized molecules. |
Choose the correct answer from the options given below:
Such a group of atoms is called a molecule. Obviously, there must be some force that holds these constituent atoms together in the molecules. The attractive force which holds various constituents (atoms, ions, etc.) together in different chemical species is called a chemical bond.
There are 4 types of chemical bonds which are formed by atoms or molecules to yield compounds.