Consider the given chemical reaction :
Product ''A'' is :
Product ''A'' is :
- picric acid
- oxalic acid
- acetic acid
- adipic acid
The Correct Option is D
Approach Solution - 1
The reaction of cyclohexane with potassium permanganate (\(\text{KMnO}_4\)) in an acidic medium (\(\text{H}_2\text{SO}_4\)) and heat results in the oxidation of cyclohexane to adipic acid.
Step 1: Oxidation of cyclohexane
Cyclohexane (\(\text{C}_6\text{H}_{12}\)) undergoes oxidation in the presence of \(\text{KMnO}_4\) and \(\text{H}_2\text{SO}_4\).
- The \(\text{KMnO}_4\) oxidizes the \(-\text{CH}_2-\) groups in cyclohexane to carboxylic acid (\(-\text{COOH}\)) groups.
- This results in the formation of adipic acid (\(\text{HOOC} - (\text{CH}_2)_4 - \text{COOH}\)).
\[\text{C}_6\text{H}_{12} \rightarrow [\text{KMnO}_4, \text{H}_2\text{SO}_4, \text{Heat}] \text{HOOC} - (\text{CH}_2)_4 - \text{COOH} \, (\text{Adipic Acid})\]
Step 2: Conclusion
The product \(A\) is adipic acid.
Final Answer: (4).
Approach Solution -2
Cyclohexene is oxidized by hot acidic potassium permanganate (KMnO₄ + H₂SO₄ + heat).
Step 2: Nature of the reaction.
Hot, concentrated, acidic KMnO₄ is a strong oxidizing agent. It cleaves the carbon–carbon double bond of alkenes completely, converting both carbons of the double bond into carboxylic acid groups if possible.
Step 3: Apply oxidation on cyclohexene.
Cyclohexene (C₆H₁₀) contains a double bond within a six-membered ring. When oxidized under these strong conditions, the ring is cleaved at the double bond, and each carbon of the double bond is converted into a carboxylic acid (-COOH).
Step 4: Product formed.
Thus, the product formed is a dicarboxylic acid with six carbons — adipic acid (hexanedioic acid).
Step 5: Final Answer.
The product "A" is adipic acid.
Top Questions on Reaction Mechanisms & Synthesis
- The reaction represented by \( A \rightarrow B \) follows first-order kinetics. At a given temperature, 20% of the reaction is completed in 223 s. The time taken to complete 50% of the reaction at the same temperature is _________ s (rounded off to the nearest integer).
- GATE MT - 2025
- Mineral Processing and Extractive Metallurgy
- Reaction Mechanisms & Synthesis
- Consider the following reactions and their standard Gibbs free energies (in J): \[ {Fe(s)} + \frac{1}{2} {O}_2(g) \rightleftharpoons {FeO(s)} \quad \Delta G^\circ = -264900 + 65T \] \[ 2 {H}_2(g) + {O}_2(g) \rightleftharpoons 2 {H}_2{O(g)} \quad \Delta G^\circ = -492900 + 109T \] Assuming Fe and FeO to be pure and no solubility of gases in the solids, the value of \( \frac{p_{H_2O}}{p_{H_2}} \) required to reduce solid FeO to solid Fe at 1000 K is _________ (rounded off to two decimal places). Given: Ideal gas constant \( R = 8.314 \, {J mol}^{-1} {K}^{-1} \).
- GATE MT - 2025
- Mineral Processing and Extractive Metallurgy
- Reaction Mechanisms & Synthesis
- Molten steel at 1900 K having dissolved hydrogen needs to be vacuum degassed. The equilibrium partial pressure of hydrogen to be maintained to achieve 1 ppm (mass basis) of dissolved hydrogen is ......... Torr (rounded off to two decimal places). Given: For the hydrogen dissolution reaction in molten steel \( \left( \frac{1}{2} {H}_2(g) = [{H}] \right) \), the equilibrium constant (expressed in terms of ppm of dissolved H) is: \[ \log_{10} K_{eq} = \frac{1900}{T} + 2.4 \] 1 atm = 760 Torr.
- GATE MT - 2025
- Mineral Processing and Extractive Metallurgy
- Reaction Mechanisms & Synthesis
- Consider the gas phase reaction: \[ CO + \frac{1}{2} O_2 \rightleftharpoons CO_2 \] At equilibrium for a particular temperature, the partial pressures of \( CO \), \( O_2 \), and \( CO_2 \) are found to be \( 10^{-6} \, {atm} \), \( 10^{-6} \, {atm} \), and \( 16 \, {atm} \), respectively. The equilibrium constant for the reaction is ......... \( \times 10^{10} \) (rounded off to one decimal place).
- GATE MT - 2025
- Mineral Processing and Extractive Metallurgy
- Reaction Mechanisms & Synthesis
- In the Claisen-Schmidt reaction to prepare dibenzalacetone from 5.3 g benzaldehyde, a total of 3.51 g of product was obtained. The percentage yield in this reaction was _____.
- JEE Main - 2025
- Chemistry
- Reaction Mechanisms & Synthesis
Questions Asked in JEE Main exam
- The system of linear equations
$x + y + z = 6$
$2x + 5y + az = 36$
$x + 2y + 3z = b$
has- JEE Main - 2026
- Matrices and Determinants
- The displacement of a particle executing simple harmonic motion with time period \(T\) is expressed as \[ x(t)=A\sin\omega t, \] where \(A\) is the amplitude of oscillation. If the maximum value of the potential energy of the oscillator is found at \[ t=\frac{T}{2\beta}, \] then the value of \(\beta\) is ________.
- JEE Main - 2026
- Waves and Oscillations
- A complex number 'z' satisfy both \(|z-6|=5\) & \(|z+2-6i|=5\) simultaneously. Find the value of \(z^3 + 3z^2 - 15z + 141\).
- JEE Main - 2026
- Algebra
In the given figure, the blocks $A$, $B$ and $C$ weigh $4\,\text{kg}$, $6\,\text{kg}$ and $8\,\text{kg}$ respectively. The coefficient of sliding friction between any two surfaces is $0.5$. The force $\vec{F}$ required to slide the block $C$ with constant speed is ___ N.
(Given: $g = 10\,\text{m s}^{-2}$)
- JEE Main - 2026
- Rotational Mechanics
Two circular discs of radius \(10\) cm each are joined at their centres by a rod, as shown in the figure. The length of the rod is \(30\) cm and its mass is \(600\) g. The mass of each disc is also \(600\) g. If the applied torque between the two discs is \(43\times10^{-7}\) dyne·cm, then the angular acceleration of the system about the given axis \(AB\) is ________ rad s\(^{-2}\).
- JEE Main - 2026
- Rotational motion