Consider the following complex ions, $P, Q$ and $R$.
$P=[FeF_6]^{3-},Q=[V(H_2O)_6]^{2+} and \, R=[Fe(H_2O)_6]^{2+} $
The correct order of the complex ions, according to their spin-only magnetic moment values (in $B.M.$) is
- $R < Q < P$
- $Q < R < P$
- $R < P < Q$
- $Q < P < R$
The Correct Option is B
Solution and Explanation
where N is tr.e number of unpaired electrons. In the presence of
weak ligand (as $H_2O,CI^-,F^-) $ there is no pairing of electrons,
and electrons donated by ligands are filled in outer vacant
orbitals
In the presence of strong ligand (as $CN^-,CO,NH_3,en) $
electrons are paired and electrons from ligands are filled in
available inner orbitals
Thus, order of spin-only magnetic moment = Q < R < P
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Concepts Used:
Coordination Compounds
A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.
Coordination entity:
A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.
Ligands:
A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.