Consider the cumulative distribution function (CDF) of a random variable \( X \):
\[
F_X(x) =
\begin{cases}
0 & \text{if } x \leq -1 \\
\frac{1}{4}(x + 1)^2 & \text{if } -1 \leq x \leq 1 \\
1 & \text{if } x \geq 1
\end{cases}
\]
The value of \( P(X^2 \leq 0.25) \) is:
\[ F_X(x) = \begin{cases} 0 & \text{if } x \leq -1 \\ \frac{1}{4}(x + 1)^2 & \text{if } -1 \leq x \leq 1 \\ 1 & \text{if } x \geq 1 \end{cases} \]
The value of \( P(X^2 \leq 0.25) \) is:
Show Hint
- 0.625
- 0.25
- 0.5
- 0.5625
The Correct Option is C
Solution and Explanation
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