Step 1: Support reactions
For the beam to be in equilibrium, the sum of all forces and moments must be zero. In this case, since there are no vertical loads applied to the beam, the support reactions at \( A \) and \( B \) must be zero. Thus, there are no reactions at the supports. This means statement (A) is true.
Step 2: Shear force
Since the beam has no external loads, only moments are applied. The shear force \( V \) is the change in internal force along the length of the beam. Since there are no vertical loads, the shear force is zero everywhere along the beam. Thus, statement (B) is true.
Step 3: Bending moment
The bending moment in the beam will be affected by the applied external moments \( M \). However, since the beam is subjected to moments at the one-third points, the internal bending moment will not be zero everywhere. The bending moment is only zero at certain points depending on the beam's length and external moments, so statement (C) is false.
Step 4: Deflection
The deflection of the beam depends on the bending moments and the beam's flexural rigidity. As there are no vertical loads and the beam is simply supported, there will be deflection at various points along the beam. Therefore, statement (D) is false.
Thus, the correct answer is (A) and (B): Support reactions are zero and shear force is zero everywhere.
\[
\boxed{\text{The correct answers are (A) and (B).}}
\]
The figures, I, II, and III are parts of a sequence. Which one of the following options comes next in the sequence as IV?
For the beam and loading shown in the figure, the second derivative of the deflection curve of the beam at the mid-point of AC is given by \( \frac{\alpha M_0}{8EI} \). The value of \( \alpha \) is ........ (rounded off to the nearest integer).