Consider the beam ACDEB given in the figure. Which of the following statements is/are correct:
Let \( V_A \) and \( V_D \) be the vertical reactions at points A and D, respectively.
Using the moment equilibrium condition about point B:
\[ \sum M_B = 0 \]
We get:
\[ - V_D(4) + 4(2) + 2(6) = 0 \]
Solving for \( V_D \):
\[ V_D = 5 \, \text{kN} \]
Now, using the equilibrium of vertical forces:
\[ V_A + V_D = 5 \]
Substituting \( V_D = 5 \) kN:
\[ V_A = 0, \quad M_A = 0. \]
- At point A, the shear force is positive (+).
- At point B, the shear force is negative (−).
- The shear force remains constant in spans BC and CD.
- The bending moment at point A is zero.
- The bending moment is also zero in the spans AB and between C and D.
- The bending moment increases from C to D, then decreases towards point E.
Thus, the correct answers are (A) and (D).
For the beam and loading shown in the figure, the second derivative of the deflection curve of the beam at the mid-point of AC is given by \( \frac{\alpha M_0}{8EI} \). The value of \( \alpha \) is ........ (rounded off to the nearest integer).
In levelling between two points A and B on the opposite banks of a river, the readings are taken by setting the instrument both at A and B, as shown in the table. If the RL of A is 150.000 m, the RL of B (in m) is ....... (rounded off to 3 decimal places).