
The reaction sequence is as follows:
Step 1: Oxidation using Jones Reagent
Jones reagent (\(\text{CrO}_3 + \text{H}_2\text{SO}_4\)) oxidizes primary alcohols (\(\text{CH}_3\text{CH}_2\text{OH}\)) to carboxylic acids. Ethanol (\(\text{CH}_3\text{CH}_2\text{OH}\)) is oxidized to acetic acid (\(\text{CH}_3\text{COOH}\)).
\[\text{CH}_3\text{CH}_2\text{OH} \rightarrow [\text{JonesReagent}] \text{CH}_3\text{COOH}.\]
Step 2: Oxidation using \(\text{KMnO}_4\)
The acetic acid (\(\text{CH}_3\text{COOH}\)) is further oxidized to carbonic acid (\(\text{H}_2\text{CO}_3\)) by \(\text{KMnO}_4\). Carbonic acid is unstable and decomposes to \(\text{CO}_2\) and water.
\[\text{CH}_3\text{COOH} \rightarrow [\text{KMnO}_4]\text{H}_2\text{CO}_3 \rightarrow \text{CO}_2 + \text{H}_2\text{O}.\]
Step 3: Decarboxylation using Soda Lime
The carbon dioxide (\(\text{CO}_2\)) reacts with soda lime (\(\text{NaOH} + \text{CaO}\)) to form methane (\(\text{CH}_4\)) via decarboxylation.
\[\text{CO}_2 + \text{NaOH} \rightarrow \text{CH}_4 + \text{Na}_2\text{CO}_3.\]
Final Product:
The major product \(P\) is methane (\(\text{CH}_4\)).
Final Answer: (1).
If the system of equations \[ (\lambda - 1)x + (\lambda - 4)y + \lambda z = 5 \] \[ \lambda x + (\lambda - 1)y + (\lambda - 4)z = 7 \] \[ (\lambda + 1)x + (\lambda + 2)y - (\lambda + 2)z = 9 \] has infinitely many solutions, then \( \lambda^2 + \lambda \) is equal to:
The output of the circuit is low (zero) for:

(A) \( X = 0, Y = 0 \)
(B) \( X = 0, Y = 1 \)
(C) \( X = 1, Y = 0 \)
(D) \( X = 1, Y = 1 \)
Choose the correct answer from the options given below:
The metal ions that have the calculated spin only magnetic moment value of 4.9 B.M. are
A. $ Cr^{2+} $
B. $ Fe^{2+} $
C. $ Fe^{3+} $
D. $ Co^{2+} $
E. $ Mn^{2+} $
Choose the correct answer from the options given below
Which of the following circuits has the same output as that of the given circuit?
