Question:

Consider a thin spherical shell of radius $R$ consisting of uniform surface charge density $\sigma$ The electric field at a point of distance $x$ from its centre and outside the shell is

Updated On: Jun 6, 2024
  • inversely proportional to $\sigma$
  • directly proportional to $x^{2}$
  • directly proportional to $ \sigma $
  • inversely proportional to $x^{2}$
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The Correct Option is D

Solution and Explanation

For a thin uniformly charged spherical shell, the field points outside the shell at a distance $x$ from the centre is
$E=\frac{1}{4 \pi \varepsilon_{0}} \frac{Q}{x^{2}}$
If the radius of the sphere is
$R, Q=\sigma 4 \pi R^{2}$
$\therefore E=\frac{1}{4 \pi \varepsilon_{0}} \frac{\sigma 4 \pi R^{2}}{x^{2}}=\frac{\sigma R^{2}}{\varepsilon_{0} x^{2}}$
This is inversely proportional to square of the distance from the centre. It is as if the whole charge is concentrated at the centre.
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Concepts Used:

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It is the property of subatomic particles that experiences a force when put in an electric and magnetic field.

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Types of electric charge

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Negative Charge - When an object has a negative charge it means that it has more electrons than protons.

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When there is an identical number of positive and negative charges, the negative and positive charges would cancel out each other and the object would become neutral.