Step 1: Understand the problem.
We are given a pipeline system with 4 segments and a time of 20 ns per segment. The pipeline processes 100 tasks in sequence, while a non-pipeline system processes each task in 4 times the segment time, i.e., 80 ns per task. The goal is to find the speedup of the pipeline system over the non-pipeline system.
Step 2: Time taken for processing 100 tasks in a non-pipeline system.
In the non-pipeline system, the total time taken for 100 tasks is:
\[
t_n = k t_p \times n = 4 \times 20 \, \text{ns} \times 100 = 8000 \, \text{ns}.
\]
Step 3: Time taken for processing 100 tasks in the pipeline system.
In the pipeline system, the first task takes \( 4 \times 20 \, \text{ns} = 80 \, \text{ns} \), and subsequent tasks are processed in parallel, taking 20 ns for each task. Thus, the time for 100 tasks is:
\[
t_p = t_p + (n - k) t_p = 80 \, \text{ns} + (100 - 4) \times 20 \, \text{ns} = 80 \, \text{ns} + 1920 \, \text{ns} = 2000 \, \text{ns}.
\]
Step 4: Speedup calculation.
The speedup of the pipeline system over the non-pipeline system is given by:
\[
\text{Speedup} = \frac{t_n}{t_p} = \frac{8000 \, \text{ns}}{2000 \, \text{ns}} = 4.
\]
Step 5: Conclusion.
Thus, the speedup of the pipeline processing over an equivalent non-pipeline processing is 3.88.
The major difficulties that cause the instruction pipeline to deviate from its normal operation are:
(A) Resource conflicts
(B) Stack operation
(C) Data dependency
(D) Branch difficulties
from the options given below: Choose the correct answer from the options given below:
Consider the following four words, out of which three are alike in some manner and one is different.
(A) Arrow
(B) Missile
(C) Sword
(D) Bullet
Choose the combination that has alike words.
Find the next two terms of the series:
The given series is: \( A, C, F, J, ? \).
(A) O
(B) U
(C) R
(D) V
Choose the correct answer from the options given below:
