Question:

Consider a one-dimensional infinite potential well of width \(a\). This system contains five non-interacting electrons, each of mass \(m\), at temperature \(T = 0 \, K\). The energy of the highest occupied state is:

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Each energy level in a 1D potential well can accommodate two electrons. The highest occupied level at \(T = 0 K\) defines the Fermi energy.
Updated On: Dec 8, 2025
  • \(\dfrac{25\pi^2 \hbar^2}{2ma^2}\)
  • \(\dfrac{10\pi^2 \hbar^2}{2ma^2}\)
  • \(\dfrac{5\pi^2 \hbar^2}{2ma^2}\)
  • \(\dfrac{9\pi^2 \hbar^2}{2ma^2}\)
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The Correct Option is D

Solution and Explanation

Step 1: Allowed energy levels. 
For an infinite potential well, \[ E_n = \frac{n^2 \pi^2 \hbar^2}{2ma^2} \]

Step 2: Electron filling at \(T = 0 K\). 
Each energy level can hold two electrons (due to spin degeneracy). For 5 electrons, levels fill as follows: 

- \(n = 1\): 2 electrons 

- \(n = 2\): 2 electrons 

- \(n = 3\): 1 electron 

Thus, the highest occupied level corresponds to \(n = 3\).

Step 3: Calculate energy. 
\[ E_3 = \frac{9\pi^2 \hbar^2}{2ma^2} \] 

Step 4: Conclusion. 
Hence, \(E = \dfrac{9\pi^2 \hbar^2}{2ma^2}\). 
 

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