Step 1: Allowed energy levels.
For an infinite potential well, \[ E_n = \frac{n^2 \pi^2 \hbar^2}{2ma^2} \]
Step 2: Electron filling at \(T = 0 K\).
Each energy level can hold two electrons (due to spin degeneracy). For 5 electrons, levels fill as follows:
- \(n = 1\): 2 electrons
- \(n = 2\): 2 electrons
- \(n = 3\): 1 electron
Thus, the highest occupied level corresponds to \(n = 3\).
Step 3: Calculate energy.
\[ E_3 = \frac{9\pi^2 \hbar^2}{2ma^2} \]
Step 4: Conclusion.
Hence, \(E = \dfrac{9\pi^2 \hbar^2}{2ma^2}\).
