A ray of light enters the transparent side of a glass slab at an angle of incidence \(\theta\). Due to the refractive index \(\mu = 1.5\), the ray undergoes refraction and bends towards the normal inside the slab.
It then reaches the silvered surface (back side), where it undergoes reflection (as if hitting a mirror). The reflected ray travels back through the slab and finally emerges from the initial side into the air, undergoing refraction again.
In this setup, due to the combination of refraction and reflection, the emergent ray deviates by \(90^\circ\) from its original direction. This is a special case where the light path effectively makes a right-angle turn due to the geometry and nature of the slab.
Thus, the deviation is: \(\boxed{90^\circ}\)
Two light beams fall on a transparent material block at point 1 and 2 with angle \( \theta_1 \) and \( \theta_2 \), respectively, as shown in the figure. After refraction, the beams intersect at point 3 which is exactly on the interface at the other end of the block. Given: the distance between 1 and 2, \( d = 4/3 \) cm and \( \theta_1 = \theta_2 = \cos^{-1} \frac{n_2}{2n_1} \), where \( n_2 \) is the refractive index of the block and \( n_1 \) is the refractive index of the outside medium, then the thickness of the block is cm.