Since the disc completes \(\frac{1}{8}\) of a rotation, the time for \(\frac{1}{8}\) rotation is \(\frac{T}{8}\), where T is the period of the disc.
The period T is given by \(T=\frac{2\pi}{\omega}\)
Therefore, the time for 1/8 rotation is \(t = \frac{T}{8} = \frac{2\pi}{8\omega} = \frac{\pi}{4\omega}\)
X- coordinate of P = ωRt
\(= \frac{πR}{4} \gt Rcos45\degree\)
Therefore, P and Q lands in the unshaded region.
So. the correct option is (D): both P and Q land in the shaded region
A string of length \( L \) is fixed at one end and carries a mass of \( M \) at the other end. The mass makes \( \frac{3}{\pi} \) rotations per second about the vertical axis passing through the end of the string as shown. The tension in the string is ________________ ML.
Let $ S $ denote the locus of the point of intersection of the pair of lines $$ 4x - 3y = 12\alpha,\quad 4\alpha x + 3\alpha y = 12, $$ where $ \alpha $ varies over the set of non-zero real numbers. Let $ T $ be the tangent to $ S $ passing through the points $ (p, 0) $ and $ (0, q) $, $ q > 0 $, and parallel to the line $ 4x - \frac{3}{\sqrt{2}} y = 0 $.
Then the value of $ pq $ is
Let $ y(x) $ be the solution of the differential equation $$ x^2 \frac{dy}{dx} + xy = x^2 + y^2, \quad x > \frac{1}{e}, $$ satisfying $ y(1) = 0 $. Then the value of $ 2 \cdot \frac{(y(e))^2}{y(e^2)} $ is ________.