Since the disc completes \(\frac{1}{8}\) of a rotation, the time for \(\frac{1}{8}\) rotation is \(\frac{T}{8}\), where T is the period of the disc.
The period T is given by \(T=\frac{2\pi}{\omega}\)
Therefore, the time for 1/8 rotation is \(t = \frac{T}{8} = \frac{2\pi}{8\omega} = \frac{\pi}{4\omega}\)
X- coordinate of P = ωRt
\(= \frac{πR}{4} \gt Rcos45\degree\)
Therefore, P and Q lands in the unshaded region.
So. the correct option is (D): both P and Q land in the shaded region