Question

Consider a binary number with m digits, where m is an even number. This binary number has alternating 1's and 0's, with digit 1 in the highest place value. The decimal equivalent of this binary number is

• A. 2^m-1
• B. \(\frac{(2^m-1)}{3}\)
• C. \(\frac{(2^{m+1}-1)}{3}\)
• D. \(\frac{2}{3}(2^m-1)\)

Answer 1

The Correct Option is D

The correct answer is (D) : \(\frac{(2^{m+1}-1)}{3}\)