Question

Which one among the following stations is visited the largest number of times?

• A. Station F
• B. Station D
• C. Station E
• D. Station C
• A. Team 4
• B. Team 1
• C. Team 3
• D. Team 2
• A. 2
• B. 4
• C. 3
• D. 1

Answer 1

The Correct Option is C

Given :
At 9:00 a.m., it's understood that all four teams have selected distinct paths from the starting point since no street sees more than one team traveling in any direction simultaneously.
At 10:00 a.m., we know Team 2 is at station E, and Team 3 is at station D. Moreover, only Team 1 and Team 4 patrol the street connecting stations A and E.
This scenario is only possible if Team 2 traveled from A to E through F, and Team 3 arrived at station D via station C.
Also, it's confirmed that only Teams 1 and 3 are at Station E by 10:30 a.m., and Team 4 avoids passing through Stations B, D, or F. Consequently, Team 1 likely opted for the (A-B) route initially, while Team 4 likely selected the (A-E) route at 9:00 a.m.
So, Team 1 is expected to arrive at B by 9:30 a.m., return to A by 10:00 a.m., and then proceed to E by 10:30 a.m.
Given that Team 4 avoids stations B, D, and F, they can only travel through stations A, E, and C. Therefore, Team 4's routes to reach station E by 11:30 could either be (A-E-A-C-A-E) or (A-E-A-E-A-E).
Given that Team 1 is already en route from A to E at 10:00 a.m., Team 4 cannot opt for the same route at that time. Therefore, the definitive route for Team 4 to reach E by 11:30 a.m. is (A-E-A-C-A-E), and by 12:00 p.m., Team 4 will return to station A.
Therefore, the complete route map for Team 4 is (A-E-A-C-A-E-A).

Teams	9.00	9.30	10.00	10.30	11.00	11.30	12.00
1	A	B	A	E
2	A	F	E
3	A	C	D
4	A	E	A	C	A	E	A

Observing that Team 1 arrives at station E by 10:30 a.m., we note that they will reach station B by 11:30 a.m., indicating they must travel to B via A.
Therefore, the complete route plan for Team 1 is (A-B-A-E-A-B-A). Additionally, it's confirmed that Teams 1 and 3 are the sole occupants of station E at 10:30 a.m.

Teams	9.00	9.30	10.00	10.30	11.00	11.30	12.00
1	A	B	A	E	A	B	A
2	A	F	E
3	A	C	D	E
4	A	E	A	C	A	E	A

At 10:00 a.m., Team 2 has only one option: they must go from E to F since Team 3 is already on the E to D route. For Team 3 to reach A by 12:00 p.m., their only feasible route is E-D-C-A.

Teams	9.00	9.30	10.00	10.30	11.00	11.30	12.00
1	A	B	A	E	A	B	A
2	A	F	E	F
3	A	C	D	E	D	C	A
4	A	E	A	C	A	E	A

So, At 10:30 a.m., Team 2's possible routes back to A are either (F-A-F-A) or (F-E-F-A).
Therefore, the final table is as follows :

Teams	9.00	9.30	10.00	10.30	11.00	11.30	12.00
1	A	B	A	E	A	B	A
2	A	F	E	F	A/E	F	A
3	A	C	D	E	D	C	A
4	A	E	A	C	A	E	A

From the above table , we can see that among the options given, Station E is the station visited the largest number of times.

So, the correct option is (C) : Station E.

Answer 2

Given :
At 9:00 a.m., it's understood that all four teams have selected distinct paths from the starting point since no street sees more than one team traveling in any direction simultaneously.
At 10:00 a.m., we know Team 2 is at station E, and Team 3 is at station D. Moreover, only Team 1 and Team 4 patrol the street connecting stations A and E.
This scenario is only possible if Team 2 traveled from A to E through F, and Team 3 arrived at station D via station C.
Also, it's confirmed that only Teams 1 and 3 are at Station E by 10:30 a.m., and Team 4 avoids passing through Stations B, D, or F. Consequently, Team 1 likely opted for the (A-B) route initially, while Team 4 likely selected the (A-E) route at 9:00 a.m.
So, Team 1 is expected to arrive at B by 9:30 a.m., return to A by 10:00 a.m., and then proceed to E by 10:30 a.m.
Given that Team 4 avoids stations B, D, and F, they can only travel through stations A, E, and C. Therefore, Team 4's routes to reach station E by 11:30 could either be (A-E-A-C-A-E) or (A-E-A-E-A-E).
Given that Team 1 is already en route from A to E at 10:00 a.m., Team 4 cannot opt for the same route at that time. Therefore, the definitive route for Team 4 to reach E by 11:30 a.m. is (A-E-A-C-A-E), and by 12:00 p.m., Team 4 will return to station A.
Therefore, the complete route map for Team 4 is (A-E-A-C-A-E-A).

Teams	9.00	9.30	10.00	10.30	11.00	11.30	12.00
1	A	B	A	E
2	A	F	E
3	A	C	D
4	A	E	A	C	A	E	A

Observing that Team 1 arrives at station E by 10:30 a.m., we note that they will reach station B by 11:30 a.m., indicating they must travel to B via A.
Therefore, the complete route plan for Team 1 is (A-B-A-E-A-B-A). Additionally, it's confirmed that Teams 1 and 3 are the sole occupants of station E at 10:30 a.m.

Teams	9.00	9.30	10.00	10.30	11.00	11.30	12.00
1	A	B	A	E	A	B	A
2	A	F	E
3	A	C	D	E
4	A	E	A	C	A	E	A

At 10:00 a.m., Team 2 has only one option: they must go from E to F since Team 3 is already on the E to D route. For Team 3 to reach A by 12:00 p.m., their only feasible route is E-D-C-A.

Teams	9.00	9.30	10.00	10.30	11.00	11.30	12.00
1	A	B	A	E	A	B	A
2	A	F	E	F
3	A	C	D	E	D	C	A
4	A	E	A	C	A	E	A

So, At 10:30 a.m., Team 2's possible routes back to A are either (F-A-F-A) or (F-E-F-A).
Therefore, the final table is as follows :

Teams	9.00	9.30	10.00	10.30	11.00	11.30	12.00
1	A	B	A	E	A	B	A
2	A	F	E	F	A/E	F	A
3	A	C	D	E	D	C	A
4	A	E	A	C	A	E	A

From the data available in the above table , we can see that the teams have crossed the B Station 2 times in the given time period.

So, the correct answer is 2.

Answer 3

Given :
At 9:00 a.m., it's understood that all four teams have selected distinct paths from the starting point since no street sees more than one team traveling in any direction simultaneously.
At 10:00 a.m., we know Team 2 is at station E, and Team 3 is at station D. Moreover, only Team 1 and Team 4 patrol the street connecting stations A and E.
This scenario is only possible if Team 2 traveled from A to E through F, and Team 3 arrived at station D via station C.
Also, it's confirmed that only Teams 1 and 3 are at Station E by 10:30 a.m., and Team 4 avoids passing through Stations B, D, or F. Consequently, Team 1 likely opted for the (A-B) route initially, while Team 4 likely selected the (A-E) route at 9:00 a.m.
So, Team 1 is expected to arrive at B by 9:30 a.m., return to A by 10:00 a.m., and then proceed to E by 10:30 a.m.
Given that Team 4 avoids stations B, D, and F, they can only travel through stations A, E, and C. Therefore, Team 4's routes to reach station E by 11:30 could either be (A-E-A-C-A-E) or (A-E-A-E-A-E).
Given that Team 1 is already en route from A to E at 10:00 a.m., Team 4 cannot opt for the same route at that time. Therefore, the definitive route for Team 4 to reach E by 11:30 a.m. is (A-E-A-C-A-E), and by 12:00 p.m., Team 4 will return to station A.
Therefore, the complete route map for Team 4 is (A-E-A-C-A-E-A).

Teams	9.00	9.30	10.00	10.30	11.00	11.30	12.00
1	A	B	A	E
2	A	F	E
3	A	C	D
4	A	E	A	C	A	E	A

Observing that Team 1 arrives at station E by 10:30 a.m., we note that they will reach station B by 11:30 a.m., indicating they must travel to B via A.
Therefore, the complete route plan for Team 1 is (A-B-A-E-A-B-A). Additionally, it's confirmed that Teams 1 and 3 are the sole occupants of station E at 10:30 a.m.

Teams	9.00	9.30	10.00	10.30	11.00	11.30	12.00
1	A	B	A	E	A	B	A
2	A	F	E
3	A	C	D	E
4	A	E	A	C	A	E	A

At 10:00 a.m., Team 2 has only one option: they must go from E to F since Team 3 is already on the E to D route. For Team 3 to reach A by 12:00 p.m., their only feasible route is E-D-C-A.

Teams	9.00	9.30	10.00	10.30	11.00	11.30	12.00
1	A	B	A	E	A	B	A
2	A	F	E	F
3	A	C	D	E	D	C	A
4	A	E	A	C	A	E	A

So, At 10:30 a.m., Team 2's possible routes back to A are either (F-A-F-A) or (F-E-F-A).
Therefore, the final table is as follows :

Teams	9.00	9.30	10.00	10.30	11.00	11.30	12.00
1	A	B	A	E	A	B	A
2	A	F	E	F	A/E	F	A
3	A	C	D	E	D	C	A
4	A	E	A	C	A	E	A

From the above table, we can infer that at 10:15am Team 3 is travelling from Station D to Station E.

So, the correct option is (C) : Team 3.

Answer 4

Given :
At 9:00 a.m., it's understood that all four teams have selected distinct paths from the starting point since no street sees more than one team traveling in any direction simultaneously.
At 10:00 a.m., we know Team 2 is at station E, and Team 3 is at station D. Moreover, only Team 1 and Team 4 patrol the street connecting stations A and E.
This scenario is only possible if Team 2 traveled from A to E through F, and Team 3 arrived at station D via station C.
Also, it's confirmed that only Teams 1 and 3 are at Station E by 10:30 a.m., and Team 4 avoids passing through Stations B, D, or F. Consequently, Team 1 likely opted for the (A-B) route initially, while Team 4 likely selected the (A-E) route at 9:00 a.m.
So, Team 1 is expected to arrive at B by 9:30 a.m., return to A by 10:00 a.m., and then proceed to E by 10:30 a.m.
Given that Team 4 avoids stations B, D, and F, they can only travel through stations A, E, and C. Therefore, Team 4's routes to reach station E by 11:30 could either be (A-E-A-C-A-E) or (A-E-A-E-A-E).
Given that Team 1 is already en route from A to E at 10:00 a.m., Team 4 cannot opt for the same route at that time. Therefore, the definitive route for Team 4 to reach E by 11:30 a.m. is (A-E-A-C-A-E), and by 12:00 p.m., Team 4 will return to station A.
Therefore, the complete route map for Team 4 is (A-E-A-C-A-E-A).

Teams	9.00	9.30	10.00	10.30	11.00	11.30	12.00
1	A	B	A	E
2	A	F	E
3	A	C	D
4	A	E	A	C	A	E	A

Observing that Team 1 arrives at station E by 10:30 a.m., we note that they will reach station B by 11:30 a.m., indicating they must travel to B via A.
Therefore, the complete route plan for Team 1 is (A-B-A-E-A-B-A). Additionally, it's confirmed that Teams 1 and 3 are the sole occupants of station E at 10:30 a.m.

Teams	9.00	9.30	10.00	10.30	11.00	11.30	12.00
1	A	B	A	E	A	B	A
2	A	F	E
3	A	C	D	E
4	A	E	A	C	A	E	A

At 10:00 a.m., Team 2 has only one option: they must go from E to F since Team 3 is already on the E to D route. For Team 3 to reach A by 12:00 p.m., their only feasible route is E-D-C-A.

Teams	9.00	9.30	10.00	10.30	11.00	11.30	12.00
1	A	B	A	E	A	B	A
2	A	F	E	F
3	A	C	D	E	D	C	A
4	A	E	A	C	A	E	A

So, At 10:30 a.m., Team 2's possible routes back to A are either (F-A-F-A) or (F-E-F-A).
Therefore, the final table is as follows :

Teams	9.00	9.30	10.00	10.30	11.00	11.30	12.00
1	A	B	A	E	A	B	A
2	A	F	E	F	A/E	F	A
3	A	C	D	E	D	C	A
4	A	E	A	C	A	E	A

From the above table, we can easily see that only the Team 4 is passing through the Station E twice a day i.e 2 times in a day.

So, the correct answer is 2.

Answer 5

Given :
At 9:00 a.m., it's understood that all four teams have selected distinct paths from the starting point since no street sees more than one team traveling in any direction simultaneously.
At 10:00 a.m., we know Team 2 is at station E, and Team 3 is at station D. Moreover, only Team 1 and Team 4 patrol the street connecting stations A and E.
This scenario is only possible if Team 2 traveled from A to E through F, and Team 3 arrived at station D via station C.
Also, it's confirmed that only Teams 1 and 3 are at Station E by 10:30 a.m., and Team 4 avoids passing through Stations B, D, or F. Consequently, Team 1 likely opted for the (A-B) route initially, while Team 4 likely selected the (A-E) route at 9:00 a.m.
So, Team 1 is expected to arrive at B by 9:30 a.m., return to A by 10:00 a.m., and then proceed to E by 10:30 a.m.
Given that Team 4 avoids stations B, D, and F, they can only travel through stations A, E, and C. Therefore, Team 4's routes to reach station E by 11:30 could either be (A-E-A-C-A-E) or (A-E-A-E-A-E).
Given that Team 1 is already en route from A to E at 10:00 a.m., Team 4 cannot opt for the same route at that time. Therefore, the definitive route for Team 4 to reach E by 11:30 a.m. is (A-E-A-C-A-E), and by 12:00 p.m., Team 4 will return to station A.
Therefore, the complete route map for Team 4 is (A-E-A-C-A-E-A).

Teams	9.00	9.30	10.00	10.30	11.00	11.30	12.00
1	A	B	A	E
2	A	F	E
3	A	C	D
4	A	E	A	C	A	E	A

Observing that Team 1 arrives at station E by 10:30 a.m., we note that they will reach station B by 11:30 a.m., indicating they must travel to B via A.
Therefore, the complete route plan for Team 1 is (A-B-A-E-A-B-A). Additionally, it's confirmed that Teams 1 and 3 are the sole occupants of station E at 10:30 a.m.

Teams	9.00	9.30	10.00	10.30	11.00	11.30	12.00
1	A	B	A	E	A	B	A
2	A	F	E
3	A	C	D	E
4	A	E	A	C	A	E	A

At 10:00 a.m., Team 2 has only one option: they must go from E to F since Team 3 is already on the E to D route. For Team 3 to reach A by 12:00 p.m., their only feasible route is E-D-C-A.

Teams	9.00	9.30	10.00	10.30	11.00	11.30	12.00
1	A	B	A	E	A	B	A
2	A	F	E	F
3	A	C	D	E	D	C	A
4	A	E	A	C	A	E	A

So, At 10:30 a.m., Team 2's possible routes back to A are either (F-A-F-A) or (F-E-F-A).
Therefore, the final table is as follows :

Teams	9.00	9.30	10.00	10.30	11.00	11.30	12.00
1	A	B	A	E	A	B	A
2	A	F	E	F	A/E	F	A
3	A	C	D	E	D	C	A
4	A	E	A	C	A	E	A

From the above table, we can infer that Team 3 and Team 4 are passing through the Station C on the mentioned day.

So, the correct option is (A) : 2.