Step 1: First reaction analysis.
Chlorination in presence of UV light indicates a free-radical substitution reaction. n-Butane undergoes chlorination to give a mixture of chlorinated products, mainly secondary butyl chloride.
Step 2: Second reaction analysis.
Alkyl halides react with \(\text{NaNO}_2\) in polar aprotic solvent (DMF) to give nitroalkanes.
Secondary butyl chloride gives 2-nitrobutane.
Step 3: Identify compound A.
Since 2-nitrobutane is formed, the intermediate halide must be secondary butyl halide, which is obtained from chlorination of n-butane.
Step 4: Conclusion.
Therefore, compound A is n-butane.