Co-ordinates of the point at which the line \(2x - 7y = 14\) intersects the y-axis are :
Show Hint
To find where a line intersects the y-axis (the y-intercept):
1. Set \(x = 0\) in the equation of the line.
2. Solve for \(y\).
The point of intersection will be \((0, y)\).
To find where a line intersects the x-axis (the x-intercept):
1. Set \(y = 0\) in the equation of the line.
2. Solve for \(x\).
The point of intersection will be \((x, 0)\).
Concept: A line intersects the y-axis at a point where the x-coordinate is zero.
Step 1: Understanding the condition for y-axis intersection
When a line intersects the y-axis, the value of its x-coordinate at that point is always 0.
So, we need to find the y-coordinate when \(x=0\).
Step 2: Substitute \(x=0\) into the given equation of the line
The equation of the line is \(2x - 7y = 14\).
Substitute \(x=0\) into this equation:
\[ 2(0) - 7y = 14 \]
\[ 0 - 7y = 14 \]
\[ -7y = 14 \]
Step 3: Solve for y
Divide both sides by -7:
\[ y = \frac{14}{-7} \]
\[ y = -2 \]
Step 4: Write the coordinates of the intersection point
The x-coordinate is 0, and we found the y-coordinate to be -2.
Therefore, the coordinates of the point where the line intersects the y-axis are \((0, -2)\).
This matches option (3).