
To determine the original linear programming problem from the given initial simplex tableau, we analyze the constraints and the objective function.
The objective row in the tableau shows the coefficients of the variables \(x\), \(y\), along with \(S_i\) (slack/surplus variables) and \(A_i\) (artificial variables). Since the coefficients of the artificial variables are negative, it indicates a maximization problem.
From the tableau, we observe:
We conclude that the original linear programming problem, given the observation that the problem is a maximization one, is:
Maximize \(Z = 15x + 25y\)
Subject to:
Thus, the correct option is:
Maximize \(Z = 15x + 25y\)
subject to \(7x + 6y \geq 20\), \(3x - 2y = 18\), \(8x + 5y \leq 30\); \(x, y \geq 0\).
If the system of equations: $$ \begin{aligned} 3x + y + \beta z &= 3 \\2x + \alpha y + z &= 2 \\x + 2y + z &= 4 \end{aligned} $$ has infinitely many solutions, then the value of \( 22\beta - 9\alpha \) is:
The sum of the payoffs to the players in the Nash equilibrium of the following simultaneous game is ............
| Player Y | ||
|---|---|---|
| C | NC | |
| Player X | X: 50, Y: 50 | X: 40, Y: 30 |
| X: 30, Y: 40 | X: 20, Y: 20 | |