Question:

Choose the one false statement.

Show Hint

In nuclei with too many protons and too few neutrons, positron emission occurs, while $\beta$-decay occurs in nuclei with too few neutrons.
Updated On: Apr 1, 2025
  • Nuclei with an even number of protons and an even number of neutrons tend to be stable
  • $\gamma$-rays are high-energy photons
  • Nuclei with too few neutrons per proton tend to undergo positron ($\bar{\nu}_e$) emission
  • Nuclei with too few neutrons per proton tend to undergo $\beta$-particle ($\gamma_e$) emission
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

Nuclei with too few neutrons per proton tend to undergo \( \beta \)-particle (\( \gamma_e \)) emission, also known as beta-minus decay. In this process, a neutron in the nucleus decays into a proton, emitting an electron (beta particle) and an antineutrino. This increases the number of neutrons and reduces the number of protons, balancing the ratio of neutrons to protons in the nucleus.

On the other hand, positron emission occurs in nuclei with too many protons and too few neutrons. In positron emission (also known as beta-plus decay), a proton in the nucleus is converted into a neutron, emitting a positron and a neutrino. This decreases the number of protons and increases the number of neutrons, again balancing the neutron-to-proton ratio.

Thus, positron emission is observed in nuclei with an excess of protons and insufficient neutrons, while \( \beta \)-particle emission occurs in nuclei with too few neutrons per proton.
Was this answer helpful?
0
0