Step 1: Recall hypersolvus vs.\ subsolvus.
In the alkali-feldspar (Ab–Or) system, a hypersolvus granite crystallizes one alkali-feldspar solid solution at high $T$ (above the solvus). A subsolvus granite crystallizes two feldspars: a K-rich alkali feldspar and an Ab-rich plagioclase; compositions lie on opposite sides of the solvus.
Step 2: Apply to Or$_{50$Ab$_{50}$.}
An intermediate composition like Or$_{50}$Ab$_{50}$ can exist as a single alkali-feldspar crystal only above the solvus (hypersolvus conditions). On cooling it exsolves to perthite. Under subsolvus conditions, the melt partitions into two coexisting feldspars rather than a single intermediate-composition feldspar; hence Or$_{50}$Ab$_{50}$ does not crystallize as one phase.
Final Answer:
\[
\boxed{\text{(A) Hypersolvus only; not subsolvus.}}
\]


Based on the given mineral proportions, which one of the following statements is CORRECT?
Rock X: \(\text{Olivine : Orthopyroxene : Clinopyroxene :: 50 : 30 : 20}\)
Rock Y: \(\text{Plagioclase : Alkali feldspar : Quartz :: 25 : 45 : 30} \)
Rock Z: \(\text{Biotite : Plagioclase : Alkali feldspar : Quartz :: 20 : 25 : 35 : 20}\)