The disproportionation reaction of chlorine in alkaline medium can be balanced as follows. Chlorine (Cl2) is both reduced and oxidized:
Cl2 + 2OH− → Cl− + ClO− + H2O
Thus, the values of a, b, c, and d are 1, 2, 1, and 1 respectively.
So, the correct answer is: Option (1)
A square loop of sides \( a = 1 \, {m} \) is held normally in front of a point charge \( q = 1 \, {C} \). The flux of the electric field through the shaded region is \( \frac{5}{p} \times \frac{1}{\varepsilon_0} \, {Nm}^2/{C} \), where the value of \( p \) is: