(a) \(\frac{5}{9}\), \(\frac{30}{54}\)
Dividing the fraction \(\frac{30}{54}\) by \(\frac{6 }{ 6}\), we get \(\frac{30 }{ 54} ÷ \frac{6 }{ 6}\)
= \(\frac{5 }{ 9}\).
∴ Dividing both the numerator and denominator of \(\frac{30}{54}\) by \(6\) simplifies it to \(\frac{5}{9}\), demonstrating their equal representation.
(b) \(\frac{3}{10}\), \(\frac{12}{50}\)
Dividing the fraction \(\frac{12}{50}\) by \(\frac{ 2 }{ 2}\), we get
\(\frac{12}{50}\) ÷ \(\frac{ 2 }{ 2}\) = \(\frac{6 }{ 25}\).
∴ Simplifying both \(\frac{3}{10}\) and \(\frac{12}{50}\) reveals their true identities: \(\frac{3}{10}\) remains itself, while \(\frac{12}{50}\) transforms into\(\frac{6 }{ 25}\).
This proves they aren't equal "fractions of wholes".
(c) \(\frac{7}{13}\) , \(\frac{5}{11}\)
The above fractions are already in their lowest terms.
∴ Analyzing their ratios through simplification, we discover that \(\frac{7}{13}\) and \(\frac{5}{11}\) hold distinct proportions.
Even when reduced to their irreducible forms, they represent different shares.
Complete the drawing shown in Fig. 9.14 to indicate where the free ends of the two wires should be joined to make the bulb glow