NaI is soluble in acetone but NaBr is precipitate in acetone
NaI is precipitated in acetone but NaBr is soluble in acetone
When acetone is taken in solvent transition state is highly polar
CH3CH2-Br + NaI (in acetone) → CH3-CH2-I + NaBr
NaI is soluble in acetone, but NaBr precipitates in acetone.
The correct statement is: NaI is soluble in acetone, but NaBr precipitates in acetone.


0.01 mole of an organic compound (X) containing 10% hydrogen, on complete combustion, produced 0.9 g H₂O. Molar mass of (X) is ___________g mol\(^{-1}\).
If the system of equations \[ (\lambda - 1)x + (\lambda - 4)y + \lambda z = 5 \] \[ \lambda x + (\lambda - 1)y + (\lambda - 4)z = 7 \] \[ (\lambda + 1)x + (\lambda + 2)y - (\lambda + 2)z = 9 \] has infinitely many solutions, then \( \lambda^2 + \lambda \) is equal to:
The hydrocarbons such as Haloalkanes and Haloarenes are the ones, in which one or more hydrogen atoms are replaced with halogen atoms. The main difference between Haloalkanes and Haloarenes is that Haloalkanes are derived from open chained hydrocarbons, also called alkanes, and Haloarenes are derived from aromatic hydrocarbons.