Catalyst A reduces the activation energy for a reaction by 10 kJ mol–1 at 300 K.
The ratio of rate constants,
\(\frac{Κ′ , Catalysed}{Κ,Uncatalysed}\)
is ex. The value of x is ____.[nearest integer]
[Assume that the pre-exponential factor is same in both the cases Given R = 8.31 J K–1 mol–1]
The correct answer is 4
\(In \frac{Κ′}{Κ} = \frac{E_a - E′_a}{RT} \)
\(= \frac{10 × 10³}{8.314 × 300}\)
In \(\frac{Κ′}{Κ}\) \(= \frac{100}{8.314 × 3}\)
\(\frac{Κ′}{Κ} = e^4\)
Therefore , x = 4
Let one focus of the hyperbola $ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 $ be at $ (\sqrt{10}, 0) $, and the corresponding directrix be $ x = \frac{\sqrt{10}}{2} $. If $ e $ and $ l $ are the eccentricity and the latus rectum respectively, then $ 9(e^2 + l) $ is equal to:
The largest $ n \in \mathbb{N} $ such that $ 3^n $ divides 50! is:
All reactants need to overcome certain energy, better known as activation energy in order to form products. This activation energy is the difference between the energy of the transition state and the reactant species.
Catalysis of chemical reactions is generally divided into two categories: