Calculate final volume of a gas when pressure of 60 mL gas is increased from 1 to 1.5 atm, keeping temperature constant
Calculate final volume of a gas when pressure of 60 mL gas is increased from 1 to 1.5 atm, keeping temperature constant
2 x 10–2 dm3
3 x 10–2 dm3
5 x 10–2 dm3
4 x 10–2 dm3
The Correct Option is D
Solution and Explanation
To calculate the final volume of the gas when the pressure is increased from 1 atm to 1.5 atm while keeping the temperature constant, we can use Boyle's Law,
P₁V₁ = P₂V₂
Given:
P₁ = 1 atm
P₂ = 1.5 atm
V₁ = 60 mL
On substituting
(1 atm) x (60 mL) = (1.5 atm) x V₂
60 atm·mL = 1.5 atm x V₂
V₂ = \(\frac {60\ (atm·mL) }{1.5 \ (atm) }\)
V₂ = 40 mL
Therefore, the final volume of the gas is 40 mL.That is 4 x 10-2 dm³
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Concepts Used:
Gas Laws
The gas laws were developed at the end of the 18th century, when scientists began to realize that relationships between pressure, volume and temperature of a sample of gas could be obtained which would hold to approximation for all gases.
The five gas laws are:
- Boyle’s Law, which provides a relationship between the pressure and the volume of a gas.
- Charles’s Law, which provides a relationship between the volume occupied by a gas and the absolute temperature.
- Gay-Lussac’s Law, which provides a relationship between the pressure exerted by a gas on the walls of its container and the absolute temperature associated with the gas.
- Avogadro’s Law, which provides a relationship between the volume occupied by a gas and the amount of gaseous substance.
- The Combined Gas Law (or the Ideal Gas Law), which can be obtained by combining the four laws listed above.