Question:

C is the mid-point of PQ, if P is (4, x), C is (y, -1) and Q is (-2, 4), then x and y respectively are

Updated On: Aug 20, 2025
  • -6 and 1
  • -6 and 2
  • 6 and -1
  • 6 and -2
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The Correct Option is A

Solution and Explanation

The problem states that C is the midpoint of line segment PQ. By definition, the midpoint of a line segment with endpoints \(P(x_1, y_1)\) and \(Q(x_2, y_2)\) is given by:
\[ \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \]
Here, \(P(4, x)\), \(C(y, -1)\), and \(Q(-2, 4)\). Setting up equations from the midpoint formula, we have:
1. \( \frac{4 + (-2)}{2} = y \)
2. \( \frac{x + 4}{2} = -1 \)
Now solving each equation:
For equation 1:
\[ y = \frac{4 - 2}{2} = \frac{2}{2} = 1 \]
For equation 2:
\[ \frac{x + 4}{2} = -1 \]
Multiply both sides by 2:
\[ x + 4 = -2 \]
Subtract 4 from both sides:
\[ x = -6 \]
Thus, the values of \( x \) and \( y \) are -6 and 1, respectively. Therefore, the correct answer is -6 and 1.
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