Using the formula for the velocity of an electron:
\( v = 2.18 \times 10^6 \times \frac{Z}{n} \)
For hydrogen (\( Z = 1, n = 1 \)):
\( v = 2.18 \times 10^6 \times \frac{1}{1} = 2.18 \times 10^6 \, \text{ms}^{-1} \approx 22 \times 10^5 \, \text{ms}^{-1} \)