Given, \(N = 0.abccbaabccb.................\)
\(⇒N = 0\ \overline {abccba}\)
It is clear that, \(N\) is divisible by \(11\),
\(⇒ (a+b+c) - (a + b+ c) = 0\)
Now, \(N =\frac {abccba}{999999}\)
By cancelling common factor \(11\) from numerator and denominator,
We get \(90909\) in denominator.
Therefore, we should multiply N by \(90909\) so that product is an integer
So, the correct option is (B): \(90909\)