Question:

By what percentage is the solubility of Potassium Chlorate in water increased as the water is heated from 30$^\circ$C to 80$^\circ$C?

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Percentage change is always calculated relative to the initial value, not the final value.
Updated On: Aug 5, 2025
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The Correct Option is B

Solution and Explanation

From the graph, the solubility of Potassium Chlorate (♦) is approximately: - At 30°C: $\approx 0.10 \ \text{kg/L}$ - At 80°C: $\approx 0.30 \ \text{kg/L}$ Increase in solubility: \[ 0.30 - 0.10 = 0.20 \ \text{kg/L} \] Percentage increase: \[ \frac{0.20}{0.10} \times 100 = 200% \] Thus, the solubility increases by 200% when heating from 30°C to 80°C.
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