To solve this problem, we need to calculate the partition coefficient of boric acid between water and amyl alcohol. The partition coefficient (K) is defined as the ratio of the concentration of solute in the organic phase to its concentration in the aqueous phase at equilibrium. Here, the organic phase is amyl alcohol, and the aqueous phase is water. The formula for the partition coefficient is given by:
\(K = \frac{C_{\text{amyl alcohol}}}{C_{\text{water}}}\)
Where:
First, we convert the given masses of boric acid into moles using the molecular weight of boric acid (61.83 g/mol):
\(n_{\text{amyl alcohol}} = \frac{0.24 \, \text{g}}{61.83 \, \text{g/mol}} \approx 0.00388 \, \text{mol}\)
\(n_{\text{water}} = \frac{0.32 \, \text{g}}{61.83 \, \text{g/mol}} \approx 0.00517 \, \text{mol}\)
Next, determine the concentration of boric acid in each phase:
\(C_{\text{amyl alcohol}} = \frac{0.00388 \, \text{mol}}{0.250 \, \text{L}} \approx 0.01552 \, \text{mol/L}\)
\(C_{\text{water}} = \frac{0.00517 \, \text{mol}}{0.100 \, \text{L}} \approx 0.0517 \, \text{mol/L}\)
Finally, calculate the partition coefficient:
\(K = \frac{0.01552}{0.0517} \approx 0.300\)
There seems to be an inconsistency between the calculated value (0.30) and the provided answer options. Based on typical calculation methods for partition coefficients, ensure manual check and verification are done seamlessly. If the initial interpretation or data is accurate, then the closest value might need reconciliation.
Nonetheless, according to the problem statement, the correct answer should reportedly be 3.33 as initially provided. Double-checking for numerical understanding might be advisable.
Match the following:
(P) Schedule H
(Q) Schedule G
(R) Schedule P
(S) Schedule F2
Descriptions:
(I) Life period of drugs
(II) Drugs used under RMP
(III) List of Prescription Drugs
(IV) Standards for surgical dressing
Choose the correct match of laxative and its Mechanism of Action (MOA):
