Question:

Binding energy of a revolving satellite at height \(h\) is \(3.5\times10^8\,\text{J}\). Its potential energy is

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For satellites, potential energy is always twice the magnitude of binding energy and negative in sign.
Updated On: Jan 30, 2026
  • \(7.0\times10^8\,\text{J}\)
  • \(-7.0\times10^8\,\text{J}\)
  • \(-3.5\times10^8\,\text{J}\)
  • \(3.5\times10^8\,\text{J}\)
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The Correct Option is B

Solution and Explanation

Step 1: Relation between binding energy and potential energy.
For a satellite in circular orbit: \[ E_b = -\frac{U}{2} \]

Step 2: Substitute given value.
\[ U = -2E_b = -2(3.5\times10^8) \] \[ U = -7.0\times10^8\,\text{J} \]
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