Question

$\begin{vmatrix} 1+a & 1 & 1 & 1 \\ 1 & 1+b & 1 & 1 \\ 1 & 1 & 1+c & 1 \\ 1 & 1 & 1 & 1=d  \end{vmatrix}$ is equal to

• A. $\frac{1}{abcd}(1+\frac1{a}+\frac1{b} + \frac1{c} + \frac1{d})$
• B. abcd(1+a+b+c+d)
• C.
• D. $abcd(1+\frac1{a}+\frac1{b} + \frac1{c} + \frac1{d})$

Answer 1

The Correct Option is D

The Correct answer is option (D) : $abcd(1+\frac1{a}+\frac1{b} + \frac1{c} + \frac1{d})$