Question:
\(\begin{bmatrix}2&3 \\ 5&7\end{bmatrix}\!\begin{bmatrix}2 \\ 5\end{bmatrix}=\ \ ?\)
\(\begin{bmatrix}2&3 \\ 5&7\end{bmatrix}\!\begin{bmatrix}2 \\ 5\end{bmatrix}=\ \ ?\)
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\((2\times2)(2\times1)\Rightarrow(2\times1)\) — size check prevents mistakes.
Updated On: Oct 17, 2025
\(\begin{bmatrix}4 \\ 25\end{bmatrix}\)
\(\begin{bmatrix}4 \\ 10 \\ 35\end{bmatrix}\)
\(\begin{bmatrix}19 \\ 45\end{bmatrix}\)
\(\begin{bmatrix}19 \\ 45\end{bmatrix}\)
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Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Row–column rule:
Top entry \(=2\cdot2+3\cdot5=4+15=19\).
Bottom entry \(=5\cdot2+7\cdot5=10+35=45\).
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