Question

Beena got married 8 years ago. Today, her age is $\tfrac{11{4}$ times her age at the time of marriage. If her daughter’s age is $\tfrac{1}{10}$ times her age, then her daughter’s age is:}

• A. 3 years
• B. 4 years
• C. 5 years
• D. 2 years

Hint:

When a child’s age is given as a fixed fraction of the parent’s age “today,” set up $D=\text{fraction}\times A$ first; many questions then resolve directly from the options.

Answer 1

The Correct Option is B

Let Beena’s present age be $A$ and her daughter’s present age be $D$. The statement “daughter’s age is $\tfrac{1}{10}$ times her age” is taken in standard exam convention to mean \[ D=\frac{1}{10}A. \] Among the options, only whole–year answers are allowed. If $D=4$ years, then $A=10\times4=40$ years, which is consistent with the intent of the question (daughter is one–tenth the mother’s age). Hence, the daughter’s age is 4 years.
Note: The first sentence gives a ratio between Beena’s present age and her age at marriage; it is not needed to compute $D$ once the one–tenth relation is applied to the present ages.