Question

A family has husband, wife, and three children A, B, and C. The present age of the husband is 5 years more than the wife's present age. Wife’s present age is twice the present age of A. The present age of A is 12 years more than the present age of B. B's present age is 2 times the present age of C. If C is 12 years old at present, what is the present age of the husband's friend Ram who is 15 years younger than the husband?

• A. 30 years
• B. 50 years
• C. 62 years
• D. 80 years

Hint:

Use simple algebra to express the relationships between the ages. Starting from the given information, work backward from C's age to find the ages of the others.

Answer 1

The Correct Option is C

Let the present age of C be $12$ years. Since B's age is 2 times C's age, B's age is $2 \times 12 = 24$ years. A's age is $12$ years more than B, so A's age is $24 + 12 = 36$ years. The wife's age is twice A's age, so the wife's age is $2 \times 36 = 72$ years. The husband's age is 5 years more than the wife's, so the husband's age is $72 + 5 = 77$ years. Ram's age is 15 years younger than the husband, so Ram's age is $77 - 15 = 62$ years. Thus, the present age of the husband's friend Ram is $62$ years.