Question:

Beena got married 8 years ago. Today, her age is \(\frac {11}{4}\) times her age at the time of marriage. If her daughter‘s age is \(\frac {1}{10}\) times her age, then her daughter‘s age is:

Updated On: Jul 27, 2024
  • 3 years
  • 4 years
  • 5 years
  • 2 years
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The Correct Option is B

Solution and Explanation

The correct option is (B): 4 years .
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