Question:
Average acceleration vector for a particle having uniform circular motion is
Average acceleration vector for a particle having uniform circular motion is
Updated On: Jul 6, 2022
- A constant vector of magnitude $v^2/r $
- a vector of magnitude $v^2/r$ directed normally to the plane of motion
- null vector
- equal to instantaneous acceleration vector at start of motion
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The Correct Option is C
Solution and Explanation
Average acceleration in uniform circular motion has zero magnitude and arbitrary direction so it is a null vector.
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Notes on Motion in a plane
Concepts Used:
Motion in a Plane
It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions.
Equations of Plane Motion
The equations of motion in a straight line are:
v=u+at
s=ut+½ at2
v2-u2=2as
Where,
- v = final velocity of the particle
- u = initial velocity of the particle
- s = displacement of the particle
- a = acceleration of the particle
- t = the time interval in which the particle is in consideration