Question:

At the pure inductive stage, find emax.

Updated On: Apr 13, 2025
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Solution and Explanation

At the pure inductive stage, the maximum voltage or \( e_{\text{max}} \) can be determined by the equation:

\[ e_{\text{max}} = I_{\text{max}} \times X_L \]

where \( I_{\text{max}} \) is the maximum current flowing through the inductor and \( X_L \) is the inductive reactance.

Inductive reactance \( X_L \) is calculated using the formula:

\[ X_L = 2\pi f L \]

where \( f \) is the frequency of the alternating current (AC) signal and \( L \) is the inductance of the inductor.

To find \( e_{\text{max}} \), you would need to know the values of \( I_{\text{max}} \), \( f \), and \( L \) for the specific circuit or scenario in question. Once you have those values, you can substitute them into the equations to calculate the maximum voltage or \( e_{\text{max}} \) at the pure inductive stage.
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Concepts Used:

Electromagnetic Induction

Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-

  1. When we place the conductor in a changing magnetic field.
  2. When the conductor constantly moves in a stationary field.

Formula:

The electromagnetic induction is mathematically represented as:-

e=N × d∅.dt

Where

  • e = induced voltage
  • N = number of turns in the coil
  • Φ = Magnetic flux (This is the amount of magnetic field present on the surface)
  • t = time

Applications of Electromagnetic Induction

  1. Electromagnetic induction in AC generator
  2. Electrical Transformers
  3. Magnetic Flow Meter